The concentration is expressed as %w/w.
1.05426
Ammonia solution
32%, EMPLURA®
Synonyme(s) :
Ammoniaque
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51,60 $
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About This Item
51,60 $
Produits recommandés
Nom du produit
Hydroxyde d′ammonium solution, EMPLURA®
Pression de vapeur
837 hPa ( 20 °C)
Niveau de qualité
Gamme de produits
EMPLURA®
Forme
liquid
Limite d'explosivité
27 %
Concentration
≥30% (NH3, acidimetric)
Impuretés
≤0.0001% Heavy metals (as Pb)
≤0.0005% Fe (Iron)
≤0.0008% Substances reducing potassium permanganate (as O)
≤0.002% Chloride (Cl)
≤0.003% Sulphate (SO?)
Résidus de calcination
≤0.003% (as sulphates)
Couleur
APHA: ≤10
pb
37.7 °C/1013 hPa
Pf
-91.5 °C
Densité
0.9 g/mL at 25 °C (lit.)
Température de stockage
2-30°C
Chaîne SMILES
[NH4+].[OH-]
InChI
1S/H3N.H2O/h1H3;1H2
Clé InChI
VHUUQVKOLVNVRT-UHFFFAOYSA-N
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Application
- Highly Efficient Recovery of Au(I) from Gold Leaching Solution Using Sodium Dimethyldithiocarbamate.: This study explores the effective recovery of gold using sodium dimethyldithiocarbamate in an ammonia-rich environment, highlighting the interaction with ammonia solution and its impact on the leaching process (Yang et al., 2024).
- Oxidation mechanism of pyrite in a thiosulfate solution: electrochemical impedance (EIS) and in situ Raman spectroscopy.: Explores the oxidation processes of pyrite in thiosulfate solutions facilitated by ammonia, examining the electrochemical properties and kinetics involved in the oxidation mechanism (Tamayo et al., 2023).
Conditionnement
Please note the following replacements:
1054261000 (1 L glass bottle) replaced by 1054261011 (1 L HDPE bottle)
1054262500 (2.5 L glass bottle) replaced by 1054262511 (2.5 L HDPE bottle)
More information about our ergonomic and unbreakable HDPE bottles can be found here: www.SigmaAldrich.com/hdpe-bottle
Remarque sur l'analyse
Identity: passes test
Colour: ≤ 10 Hazen
Chloride (Cl): ≤ 0.002 %
Sulphate (SO₄): ≤ 0.003 %
Heavy metals (as Pb): ≤ 0.0001 %
Fe (Iron): ≤ 0.0005 %
Substances reducing potassium permanganate (as O): ≤ 0.0008 %
Residue on ignition (as sulphates): ≤ 0.003 %
Informations légales
Mention d'avertissement
Danger
Mentions de danger
Conseils de prudence
Classification des risques
Aquatic Acute 1 - Aquatic Chronic 2 - Eye Dam. 1 - Skin Corr. 1B - STOT SE 3
Organes cibles
Respiratory system
Code de la classe de stockage
8B - Non-combustible, corrosive hazardous materials
Classe de danger pour l'eau (WGK)
WGK 2
Certificats d'analyse (COA)
Recherchez un Certificats d'analyse (COA) en saisissant le numéro de lot du produit. Les numéros de lot figurent sur l'étiquette du produit après les mots "Lot" ou "Batch".
Déjà en possession de ce produit ?
Retrouvez la documentation relative aux produits que vous avez récemment achetés dans la Bibliothèque de documents.
Protocoles
A guide to create solvent systems used for the thin-layer chromatography assay of Novabiochem products.
Contenu apparenté
Our ergonomic 1 L HDPE bottle for acids, bases, and solvents provide an alternative to glass chemical bottles for lab safety in pouring & handling of hazardous chemicals in the laboratory.
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Is the 32% NH3 concentration expressed as %w/w?
1 answer-
Helpful?
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Is Emplura ammonia solution 32% considered technical grade or higher purity?
1 answer-
This product is considered research grade.
Helpful?
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you say that 28% solution of NH3 is a 56.6% NH4OH for calculating molarity. Can you explain the conversion of 28% to 56.6%? What would be the molarity of a 31% NH3 solution of ammonium hydroxide?
1 answer-
It should be 57.6% NH4OH, not 56.6% NH4OH. Using 17.034 as the molecular weight for NH3 and 35.0494 as the molecular weight weight for NH4OH, the calculation would be: (28 grams NH3/100 grams of solution) X (35.0494 grams NH4OH / 17.034 grams NH3) = 57.6 grams NH4OH per 100 grams of solution, or 57.6%.
To calculate the molarity, the density of a 31% NH3 solution is needed. For the calculation, please note that the weight percentage is for NH3, molecular weight 17.034. (31 grams of NH3 / 100 grams of solution) X (890 grams of solution / Liter of solution) X (1 mole NH3 / 17.034 grams NH3) X (1 mole NH4OH / 1 mole NH3) = 16.2 (16.197) moles NH4OH per Liter. The molarity would be 16.2 M.
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