Given that the ICl content of this product is approximately 90%, the calculated value is 0.10 N.
Here is the calculation:
(10 mL ICl / 1.800 LIters solution) X (3.24 grams ICl / 1 mL ICl) X (1 mole ICl / 162.36 g ICl) = 0.11 N.
Please see the link below to review a sample Certificate of Analysis:
https://www.sigmaaldrich.com/certificates/COFA/40/402990/402990-1KG-PW_____MKCL8779__.pdf