The Aluminum content of this material is not tested. However, based on the molecular formula of Li6.24 La3 Zr2 Al0.24 O11.98, the Al content may be calculated by using the following equation:
27 (atomic weight of Al) x 0.24 / (7 x 6.24 + 139 x 3 +91 x 2 + 27 x 0.24 + 16 x 11.98) (Mw of Li6.24La3Zr2Al0.24O11.98) = 6.48 / (43.68 + 417 +182 + 6.48 +191.68) = 6.48 / 840.84 = 0.0077.
Therefore, the theoretical percentage of Aluminum is 0.77 %.